3y-1=-5(-3+y)

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Solution for 3y-1=-5(-3+y) equation: 



3y-1=-5(-3+y)

We move all terms to the left:

3y-1-(-5(-3+y))=0

We add all the numbers together, and all the variables

3y-(-5(y-3))-1=0



We calculate terms in parentheses: -(-5(y-3)), so:

-5(y-3)

We multiply parentheses

-5y+15

Back to the equation:

-(-5y+15)



We get rid of parentheses

3y+5y-15-1=0

We add all the numbers together, and all the variables

8y-16=0

We move all terms containing y to the left, all other terms to the right

8y=16

y=16/8

y=2

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