3y-1=8+7y

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Solution for 3y-1=8+7y equation: 



3y-1=8+7y

We move all terms to the left:

3y-1-(8+7y)=0

We add all the numbers together, and all the variables

3y-(7y+8)-1=0

We get rid of parentheses

3y-7y-8-1=0

We add all the numbers together, and all the variables

-4y-9=0

We move all terms containing y to the left, all other terms to the right

-4y=9

y=9/-4

y=-2+1/4

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