3y-1=8+7y

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Solution for 3y-1=8+7y equation:



3y-1=8+7y
We move all terms to the left:
3y-1-(8+7y)=0
We add all the numbers together, and all the variables
3y-(7y+8)-1=0
We get rid of parentheses
3y-7y-8-1=0
We add all the numbers together, and all the variables
-4y-9=0
We move all terms containing y to the left, all other terms to the right
-4y=9
y=9/-4
y=-2+1/4

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