3y-2(2y+11)=19

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Solution for 3y-2(2y+11)=19 equation: 



3y-2(2y+11)=19

We move all terms to the left:

3y-2(2y+11)-(19)=0

We multiply parentheses

3y-4y-22-19=0

We add all the numbers together, and all the variables

-1y-41=0

We move all terms containing y to the left, all other terms to the right

-y=41

y=41/-1

y=-41

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