3y-2(2y-5)=2(y+3)-8

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Solution for 3y-2(2y-5)=2(y+3)-8 equation: 



3y-2(2y-5)=2(y+3)-8

We move all terms to the left:

3y-2(2y-5)-(2(y+3)-8)=0

We multiply parentheses

3y-4y-(2(y+3)-8)+10=0



We calculate terms in parentheses: -(2(y+3)-8), so:

2(y+3)-8

We multiply parentheses

2y+6-8

We add all the numbers together, and all the variables

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

-1y-(2y-2)+10=0

We get rid of parentheses

-1y-2y+2+10=0

We add all the numbers together, and all the variables

-3y+12=0

We move all terms containing y to the left, all other terms to the right

-3y=-12

y=-12/-3

y=+4

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