3y-2(3-3y)=12

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Solution for 3y-2(3-3y)=12 equation: 



3y-2(3-3y)=12

We move all terms to the left:

3y-2(3-3y)-(12)=0

We add all the numbers together, and all the variables

3y-2(-3y+3)-12=0

We multiply parentheses

3y+6y-6-12=0

We add all the numbers together, and all the variables

9y-18=0

We move all terms containing y to the left, all other terms to the right

9y=18

y=18/9

y=2

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