3y-2(4y-5)=10-8y

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Solution for 3y-2(4y-5)=10-8y equation: 



3y-2(4y-5)=10-8y

We move all terms to the left:

3y-2(4y-5)-(10-8y)=0

We add all the numbers together, and all the variables

3y-2(4y-5)-(-8y+10)=0

We multiply parentheses

3y-8y-(-8y+10)+10=0

We get rid of parentheses

3y-8y+8y-10+10=0

We add all the numbers together, and all the variables

3y=0

y=0/3

y=0

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