3y-2(y+1)=11

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Solution for 3y-2(y+1)=11 equation: 



3y-2(y+1)=11

We move all terms to the left:

3y-2(y+1)-(11)=0

We multiply parentheses

3y-2y-2-11=0

We add all the numbers together, and all the variables

y-13=0

We move all terms containing y to the left, all other terms to the right

y=13

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