3y-2(y+1)=3(y-4)+6

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Solution for 3y-2(y+1)=3(y-4)+6 equation:


Simplifying
3y + -2(y + 1) = 3(y + -4) + 6

Reorder the terms:
3y + -2(1 + y) = 3(y + -4) + 6
3y + (1 * -2 + y * -2) = 3(y + -4) + 6
3y + (-2 + -2y) = 3(y + -4) + 6

Reorder the terms:
-2 + 3y + -2y = 3(y + -4) + 6

Combine like terms: 3y + -2y = 1y
-2 + 1y = 3(y + -4) + 6

Reorder the terms:
-2 + 1y = 3(-4 + y) + 6
-2 + 1y = (-4 * 3 + y * 3) + 6
-2 + 1y = (-12 + 3y) + 6

Reorder the terms:
-2 + 1y = -12 + 6 + 3y

Combine like terms: -12 + 6 = -6
-2 + 1y = -6 + 3y

Solving
-2 + 1y = -6 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-2 + 1y + -3y = -6 + 3y + -3y

Combine like terms: 1y + -3y = -2y
-2 + -2y = -6 + 3y + -3y

Combine like terms: 3y + -3y = 0
-2 + -2y = -6 + 0
-2 + -2y = -6

Add '2' to each side of the equation.
-2 + 2 + -2y = -6 + 2

Combine like terms: -2 + 2 = 0
0 + -2y = -6 + 2
-2y = -6 + 2

Combine like terms: -6 + 2 = -4
-2y = -4

Divide each side by '-2'.
y = 2

Simplifying
y = 2

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