3y-2(y+5)=10y

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Solution for 3y-2(y+5)=10y equation: 



3y-2(y+5)=10y

We move all terms to the left:

3y-2(y+5)-(10y)=0

We add all the numbers together, and all the variables

-7y-2(y+5)=0

We multiply parentheses

-7y-2y-10=0

We add all the numbers together, and all the variables

-9y-10=0

We move all terms containing y to the left, all other terms to the right

-9y=10

y=10/-9

y=-1+1/9

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