3y-2+2(5y+2)=-5(y+2)

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Solution for 3y-2+2(5y+2)=-5(y+2) equation: 



3y-2+2(5y+2)=-5(y+2)

We move all terms to the left:

3y-2+2(5y+2)-(-5(y+2))=0

We multiply parentheses

3y+10y-(-5(y+2))+4-2=0



We calculate terms in parentheses: -(-5(y+2)), so:

-5(y+2)

We multiply parentheses

-5y-10

Back to the equation:

-(-5y-10)



We add all the numbers together, and all the variables

13y-(-5y-10)+2=0

We get rid of parentheses

13y+5y+10+2=0

We add all the numbers together, and all the variables

18y+12=0

We move all terms containing y to the left, all other terms to the right

18y=-12

y=-12/18

y=-2/3

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