3y-2+y+20=6y+20-4y

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Solution for 3y-2+y+20=6y+20-4y equation: 



3y-2+y+20=6y+20-4y

We move all terms to the left:

3y-2+y+20-(6y+20-4y)=0

We add all the numbers together, and all the variables

3y+y-(2y+20)-2+20=0

We add all the numbers together, and all the variables

4y-(2y+20)+18=0

We get rid of parentheses

4y-2y-20+18=0

We add all the numbers together, and all the variables

2y-2=0

We move all terms containing y to the left, all other terms to the right

2y=2

y=2/2

y=1

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