3y-2+y=19+4y+3y

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Solution for 3y-2+y=19+4y+3y equation: 



3y-2+y=19+4y+3y

We move all terms to the left:

3y-2+y-(19+4y+3y)=0

We add all the numbers together, and all the variables

3y+y-(7y+19)-2=0

We add all the numbers together, and all the variables

4y-(7y+19)-2=0

We get rid of parentheses

4y-7y-19-2=0

We add all the numbers together, and all the variables

-3y-21=0

We move all terms containing y to the left, all other terms to the right

-3y=21

y=21/-3

y=-7

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