3y-2/2-2y+3/3=2/3-y

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Solution for 3y-2/2-2y+3/3=2/3-y equation: 



3y-2/2-2y+3/3=2/3-y

We move all terms to the left:

3y-2/2-2y+3/3-(2/3-y)=0



Domain of the equation: 3-y)!=0

We move all terms containing y to the left, all other terms to the right

-y)!=-3

y!=-3/1

y!=-3

y∈R



We add all the numbers together, and all the variables

3y-2y-(-1y+2/3)-2/2+3/3=0

We add all the numbers together, and all the variables

y-(-1y+2/3)=0

We get rid of parentheses

y+1y-2/3=0

We multiply all the terms by the denominator


y*3+1y*3-2=0

Wy multiply elements

3y+3y-2=0

We add all the numbers together, and all the variables

6y-2=0

We move all terms containing y to the left, all other terms to the right

6y=2

y=2/6

y=1/3

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