3y-2/3y=1(1/3)

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Solution for 3y-2/3y=1(1/3) equation:



3y-2/3y=1(1/3)
We move all terms to the left:
3y-2/3y-(1(1/3))=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
We add all the numbers together, and all the variables
3y-2/3y-(1(+1/3))=0
We calculate fractions
3y+()/9y^2+(-(1(+1*3y)/9y^2=0
We multiply all the terms by the denominator
3y*9y^2+(-(1(+1*3y)+()=0
We calculate terms in parentheses: +(-(1(+1*3y)+(), so:
-(1(+1*3y)+(
Wy multiply elements
27y^3+(-(1(+1*3y)+()=0
We calculate terms in parentheses: +(-(1(+1*3y)+(), so:
-(1(+1*3y)+(
We do not support eypression: y^3

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