3y-2/4=-2/y-4

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Solution for 3y-2/4=-2/y-4 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3*y-(2/4) = -2/y-4 // + -2/y-4

3*y-(-2/y)-(2/4)+4 = 0

3*y+2*y^-1-1/2+4 = 0

3*y^1+2*y^-1+7/2*y^0 = 0

(3*y^2+7/2*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(3*y^2+7/2*y^1+2*y^0) = 0

y^1

3*y^2+(7/2)*y+2 = 0

3*y^2+(7/2)*y+2 = 0

DELTA = (7/2)^2-(2*3*4)

DELTA = -47/4

DELTA < 0

y in { } 

y belongs to the empty set

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