3y-28=12

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Solution for 3y-28=12 equation: 



3y-28=12

We move all terms to the left:

3y-28-(12)=0

We add all the numbers together, and all the variables

3y-40=0

We move all terms containing y to the left, all other terms to the right

3y=40

y=40/3

y=13+1/3

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