3y-2=2(y+1)-(4-y)

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Solution for 3y-2=2(y+1)-(4-y) equation:


Simplifying
3y + -2 = 2(y + 1) + -1(4 + -1y)

Reorder the terms:
-2 + 3y = 2(y + 1) + -1(4 + -1y)

Reorder the terms:
-2 + 3y = 2(1 + y) + -1(4 + -1y)
-2 + 3y = (1 * 2 + y * 2) + -1(4 + -1y)
-2 + 3y = (2 + 2y) + -1(4 + -1y)
-2 + 3y = 2 + 2y + (4 * -1 + -1y * -1)
-2 + 3y = 2 + 2y + (-4 + 1y)

Reorder the terms:
-2 + 3y = 2 + -4 + 2y + 1y

Combine like terms: 2 + -4 = -2
-2 + 3y = -2 + 2y + 1y

Combine like terms: 2y + 1y = 3y
-2 + 3y = -2 + 3y

Add '2' to each side of the equation.
-2 + 2 + 3y = -2 + 2 + 3y

Combine like terms: -2 + 2 = 0
0 + 3y = -2 + 2 + 3y
3y = -2 + 2 + 3y

Combine like terms: -2 + 2 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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