3y-2y(y+3)=5

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Solution for 3y-2y(y+3)=5 equation: 



3y-2y(y+3)=5

We move all terms to the left:

3y-2y(y+3)-(5)=0

We multiply parentheses

-2y^2+3y-6y-5=0

We add all the numbers together, and all the variables

-2y^2-3y-5=0

a = -2; b = -3; c = -5;
Δ = b2-4ac
Δ = -32-4·(-2)·(-5)
Δ = -31
Delta is less than zero, so there is no solution for the equation

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