3y-3(3y+2)=4-2(5-y)

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Solution for 3y-3(3y+2)=4-2(5-y) equation:



3y-3(3y+2)=4-2(5-y)
We move all terms to the left:
3y-3(3y+2)-(4-2(5-y))=0
We add all the numbers together, and all the variables
3y-3(3y+2)-(4-2(-1y+5))=0
We multiply parentheses
3y-9y-(4-2(-1y+5))-6=0
We calculate terms in parentheses: -(4-2(-1y+5)), so:
4-2(-1y+5)
determiningTheFunctionDomain -2(-1y+5)+4
We multiply parentheses
2y-10+4
We add all the numbers together, and all the variables
2y-6
Back to the equation:
-(2y-6)
We add all the numbers together, and all the variables
-6y-(2y-6)-6=0
We get rid of parentheses
-6y-2y+6-6=0
We add all the numbers together, and all the variables
-8y=0
y=0/-8
y=0

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