3y-3(5y+5)=-4-5(-4-y)

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Solution for 3y-3(5y+5)=-4-5(-4-y) equation: 



3y-3(5y+5)=-4-5(-4-y)

We move all terms to the left:

3y-3(5y+5)-(-4-5(-4-y))=0

We add all the numbers together, and all the variables

3y-3(5y+5)-(-4-5(-1y-4))=0

We multiply parentheses

3y-15y-(-4-5(-1y-4))-15=0



We calculate terms in parentheses: -(-4-5(-1y-4)), so:

-4-5(-1y-4)

determiningTheFunctionDomain
-5(-1y-4)-4

We multiply parentheses

5y+20-4

We add all the numbers together, and all the variables

5y+16

Back to the equation:

-(5y+16)



We add all the numbers together, and all the variables

-12y-(5y+16)-15=0

We get rid of parentheses

-12y-5y-16-15=0

We add all the numbers together, and all the variables

-17y-31=0

We move all terms containing y to the left, all other terms to the right

-17y=31

y=31/-17

y=-1+14/17

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