3y-3+y+37=7y+40-5y

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Solution for 3y-3+y+37=7y+40-5y equation: 



3y-3+y+37=7y+40-5y

We move all terms to the left:

3y-3+y+37-(7y+40-5y)=0

We add all the numbers together, and all the variables

3y+y-(2y+40)-3+37=0

We add all the numbers together, and all the variables

4y-(2y+40)+34=0

We get rid of parentheses

4y-2y-40+34=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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