3y-33=-7(y+3)

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Solution for 3y-33=-7(y+3) equation: 



3y-33=-7(y+3)

We move all terms to the left:

3y-33-(-7(y+3))=0



We calculate terms in parentheses: -(-7(y+3)), so:

-7(y+3)

We multiply parentheses

-7y-21

Back to the equation:

-(-7y-21)



We get rid of parentheses

3y+7y+21-33=0

We add all the numbers together, and all the variables

10y-12=0

We move all terms containing y to the left, all other terms to the right

10y=12

y=12/10

y=1+1/5

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