3y-33=7(y-7)

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Solution for 3y-33=7(y-7) equation: 



3y-33=7(y-7)

We move all terms to the left:

3y-33-(7(y-7))=0



We calculate terms in parentheses: -(7(y-7)), so:

7(y-7)

We multiply parentheses

7y-49

Back to the equation:

-(7y-49)



We get rid of parentheses

3y-7y+49-33=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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