3y-3=32-4y

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Solution for 3y-3=32-4y equation: 



3y-3=32-4y

We move all terms to the left:

3y-3-(32-4y)=0

We add all the numbers together, and all the variables

3y-(-4y+32)-3=0

We get rid of parentheses

3y+4y-32-3=0

We add all the numbers together, and all the variables

7y-35=0

We move all terms containing y to the left, all other terms to the right

7y=35

y=35/7

y=5

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