3y-4(y+1)=-(6+4)+y

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Solution for 3y-4(y+1)=-(6+4)+y equation: 


Simplifying
3y + -4(y + 1) = -1(6 + 4) + y

Reorder the terms:
3y + -4(1 + y) = -1(6 + 4) + y
3y + (1 * -4 + y * -4) = -1(6 + 4) + y
3y + (-4 + -4y) = -1(6 + 4) + y

Reorder the terms:
-4 + 3y + -4y = -1(6 + 4) + y

Combine like terms: 3y + -4y = -1y
-4 + -1y = -1(6 + 4) + y

Combine like terms: 6 + 4 = 10
-4 + -1y = -1(10) + y

Multiply -1 * 10
-4 + -1y = -10 + y

Solving
-4 + -1y = -10 + y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y' to each side of the equation.
-4 + -1y + -1y = -10 + y + -1y

Combine like terms: -1y + -1y = -2y
-4 + -2y = -10 + y + -1y

Combine like terms: y + -1y = 0
-4 + -2y = -10 + 0
-4 + -2y = -10

Add '4' to each side of the equation.
-4 + 4 + -2y = -10 + 4

Combine like terms: -4 + 4 = 0
0 + -2y = -10 + 4
-2y = -10 + 4

Combine like terms: -10 + 4 = -6
-2y = -6

Divide each side by '-2'.
y = 3

Simplifying
y = 3

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