3y-4(y+1)=-(6y+4)+y

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Solution for 3y-4(y+1)=-(6y+4)+y equation:


Simplifying
3y + -4(y + 1) = -1(6y + 4) + y

Reorder the terms:
3y + -4(1 + y) = -1(6y + 4) + y
3y + (1 * -4 + y * -4) = -1(6y + 4) + y
3y + (-4 + -4y) = -1(6y + 4) + y

Reorder the terms:
-4 + 3y + -4y = -1(6y + 4) + y

Combine like terms: 3y + -4y = -1y
-4 + -1y = -1(6y + 4) + y

Reorder the terms:
-4 + -1y = -1(4 + 6y) + y
-4 + -1y = (4 * -1 + 6y * -1) + y
-4 + -1y = (-4 + -6y) + y

Combine like terms: -6y + y = -5y
-4 + -1y = -4 + -5y

Add '4' to each side of the equation.
-4 + 4 + -1y = -4 + 4 + -5y

Combine like terms: -4 + 4 = 0
0 + -1y = -4 + 4 + -5y
-1y = -4 + 4 + -5y

Combine like terms: -4 + 4 = 0
-1y = 0 + -5y
-1y = -5y

Solving
-1y = -5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '5y' to each side of the equation.
-1y + 5y = -5y + 5y

Combine like terms: -1y + 5y = 4y
4y = -5y + 5y

Combine like terms: -5y + 5y = 0
4y = 0

Divide each side by '4'.
y = 0

Simplifying
y = 0

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