3y-4(y+5)=3(y-7)-15

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Solution for 3y-4(y+5)=3(y-7)-15 equation: 



3y-4(y+5)=3(y-7)-15

We move all terms to the left:

3y-4(y+5)-(3(y-7)-15)=0

We multiply parentheses

3y-4y-(3(y-7)-15)-20=0



We calculate terms in parentheses: -(3(y-7)-15), so:

3(y-7)-15

We multiply parentheses

3y-21-15

We add all the numbers together, and all the variables

3y-36

Back to the equation:

-(3y-36)



We add all the numbers together, and all the variables

-1y-(3y-36)-20=0

We get rid of parentheses

-1y-3y+36-20=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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