3y-4+y+32=8y+30-6y

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Solution for 3y-4+y+32=8y+30-6y equation: 



3y-4+y+32=8y+30-6y

We move all terms to the left:

3y-4+y+32-(8y+30-6y)=0

We add all the numbers together, and all the variables

3y+y-(2y+30)-4+32=0

We add all the numbers together, and all the variables

4y-(2y+30)+28=0

We get rid of parentheses

4y-2y-30+28=0

We add all the numbers together, and all the variables

2y-2=0

We move all terms containing y to the left, all other terms to the right

2y=2

y=2/2

y=1

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