3y-4+y+52=8y+50-6y

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Solution for 3y-4+y+52=8y+50-6y equation:



3y-4+y+52=8y+50-6y
We move all terms to the left:
3y-4+y+52-(8y+50-6y)=0
We add all the numbers together, and all the variables
3y+y-(2y+50)-4+52=0
We add all the numbers together, and all the variables
4y-(2y+50)+48=0
We get rid of parentheses
4y-2y-50+48=0
We add all the numbers together, and all the variables
2y-2=0
We move all terms containing y to the left, all other terms to the right
2y=2
y=2/2
y=1

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