3y-4/y-40

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Solution for 3y-4/y-40 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3*y-(4/y)-4 > 0

3*y-4*y^-1-4 > 0

3*y-4*y^-1-4 = 0

3*y^1-4*y^-1-4*y^0 = 0

(3*y^2-4*y^1-4*y^0)/(y^1) = 0 // * y^2

y^1*(3*y^2-4*y^1-4*y^0) = 0

y^1

3*y^2-4*y-4 = 0

3*y^2-4*y-4 = 0

DELTA = (-4)^2-(-4*3*4)

DELTA = 64

DELTA > 0

y = (64^(1/2)+4)/(2*3) or y = (4-64^(1/2))/(2*3)

y = 2 or y = -2/3

y in { -2/3, 2} 

(y+2/3)*(y-2) > 0

	(-oo:-2/3)	(-2/3:2)	(2:+oo)
y+2/3	-	+	+
y-2	-	-	+


y in (-oo:-2/3) U (2:+oo)

(-oo:-2/3) U (2:+oo)

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