3y-41=6y+13

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Solution for 3y-41=6y+13 equation: 



3y-41=6y+13

We move all terms to the left:

3y-41-(6y+13)=0

We get rid of parentheses

3y-6y-13-41=0

We add all the numbers together, and all the variables

-3y-54=0

We move all terms containing y to the left, all other terms to the right

-3y=54

y=54/-3

y=-18

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