3y-4=16y+48

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Solution for 3y-4=16y+48 equation: 



3y-4=16y+48

We move all terms to the left:

3y-4-(16y+48)=0

We get rid of parentheses

3y-16y-48-4=0

We add all the numbers together, and all the variables

-13y-52=0

We move all terms containing y to the left, all other terms to the right

-13y=52

y=52/-13

y=-4

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