3y-4=2(y+1)

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Solution for 3y-4=2(y+1) equation: 



3y-4=2(y+1)

We move all terms to the left:

3y-4-(2(y+1))=0



We calculate terms in parentheses: -(2(y+1)), so:

2(y+1)

We multiply parentheses

2y+2

Back to the equation:

-(2y+2)



We get rid of parentheses

3y-2y-2-4=0

We add all the numbers together, and all the variables

y-6=0

We move all terms containing y to the left, all other terms to the right

y=6

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