3y-4=4(y+6)-2(y+3)

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Solution for 3y-4=4(y+6)-2(y+3) equation:



3y-4=4(y+6)-2(y+3)
We move all terms to the left:
3y-4-(4(y+6)-2(y+3))=0
We calculate terms in parentheses: -(4(y+6)-2(y+3)), so:
4(y+6)-2(y+3)
We multiply parentheses
4y-2y+24-6
We add all the numbers together, and all the variables
2y+18
Back to the equation:
-(2y+18)
We get rid of parentheses
3y-2y-18-4=0
We add all the numbers together, and all the variables
y-22=0
We move all terms containing y to the left, all other terms to the right
y=22

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