3y-5(2y+1)=-4-5(-1-y)

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Solution for 3y-5(2y+1)=-4-5(-1-y) equation: 



3y-5(2y+1)=-4-5(-1-y)

We move all terms to the left:

3y-5(2y+1)-(-4-5(-1-y))=0

We add all the numbers together, and all the variables

3y-5(2y+1)-(-4-5(-1y-1))=0

We multiply parentheses

3y-10y-(-4-5(-1y-1))-5=0



We calculate terms in parentheses: -(-4-5(-1y-1)), so:

-4-5(-1y-1)

determiningTheFunctionDomain
-5(-1y-1)-4

We multiply parentheses

5y+5-4

We add all the numbers together, and all the variables

5y+1

Back to the equation:

-(5y+1)



We add all the numbers together, and all the variables

-7y-(5y+1)-5=0

We get rid of parentheses

-7y-5y-1-5=0

We add all the numbers together, and all the variables

-12y-6=0

We move all terms containing y to the left, all other terms to the right

-12y=6

y=6/-12

y=-1/2

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