3y-5(2y+2)=-17

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Solution for 3y-5(2y+2)=-17 equation: 



3y-5(2y+2)=-17

We move all terms to the left:

3y-5(2y+2)-(-17)=0

We add all the numbers together, and all the variables

3y-5(2y+2)+17=0

We multiply parentheses

3y-10y-10+17=0

We add all the numbers together, and all the variables

-7y+7=0

We move all terms containing y to the left, all other terms to the right

-7y=-7

y=-7/-7

y=1

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