3y-5+2(3y+1)=-3(y+3)

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Solution for 3y-5+2(3y+1)=-3(y+3) equation: 



3y-5+2(3y+1)=-3(y+3)

We move all terms to the left:

3y-5+2(3y+1)-(-3(y+3))=0

We multiply parentheses

3y+6y-(-3(y+3))+2-5=0



We calculate terms in parentheses: -(-3(y+3)), so:

-3(y+3)

We multiply parentheses

-3y-9

Back to the equation:

-(-3y-9)



We add all the numbers together, and all the variables

9y-(-3y-9)-3=0

We get rid of parentheses

9y+3y+9-3=0

We add all the numbers together, and all the variables

12y+6=0

We move all terms containing y to the left, all other terms to the right

12y=-6

y=-6/12

y=-1/2

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