3y-5+7y+10=8y-3

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Solution for 3y-5+7y+10=8y-3 equation: 



3y-5+7y+10=8y-3

We move all terms to the left:

3y-5+7y+10-(8y-3)=0

We add all the numbers together, and all the variables

10y-(8y-3)+5=0

We get rid of parentheses

10y-8y+3+5=0

We add all the numbers together, and all the variables

2y+8=0

We move all terms containing y to the left, all other terms to the right

2y=-8

y=-8/2

y=-4

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