3y-5/5-2(y-59))=y-1/2

Solution for 3y-5/5-2(y-59))=y-1/2 equation:

3y-5/5-2(y-59))=y-1/2

We move all terms to the left:

3y-5/5-2(y-59))-(y-1/2)=0

We add all the numbers together, and all the variables

3y-2(y-59))-(y-1/2-1)=0

We add all the numbers together, and all the variables

3y-2(y-59))-(y-1/2=0

We multiply all the terms by the denominator


3y*2-(2(y-59))-y*2-1=0


We calculate terms in parentheses: -(2(y-59)), so:

2(y-59)

We multiply parentheses

2y-118

Back to the equation:

-(2y-118)


Wy multiply elements

6y-(2y-118)-2y-1=0

We get rid of parentheses

6y-2y-2y+118-1=0

We add all the numbers together, and all the variables

2y+117=0

We move all terms containing y to the left, all other terms to the right

2y=-117

y=-117/2

y=-58+1/2