3y-5=2(2y+3)

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Solution for 3y-5=2(2y+3) equation:



3y-5=2(2y+3)
We move all terms to the left:
3y-5-(2(2y+3))=0
We calculate terms in parentheses: -(2(2y+3)), so:
2(2y+3)
We multiply parentheses
4y+6
Back to the equation:
-(4y+6)
We get rid of parentheses
3y-4y-6-5=0
We add all the numbers together, and all the variables
-1y-11=0
We move all terms containing y to the left, all other terms to the right
-y=11
y=11/-1
y=-11

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