3y-5=8(8y+1)-3

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Solution for 3y-5=8(8y+1)-3 equation: 



3y-5=8(8y+1)-3

We move all terms to the left:

3y-5-(8(8y+1)-3)=0



We calculate terms in parentheses: -(8(8y+1)-3), so:

8(8y+1)-3

We multiply parentheses

64y+8-3

We add all the numbers together, and all the variables

64y+5

Back to the equation:

-(64y+5)



We get rid of parentheses

3y-64y-5-5=0

We add all the numbers together, and all the variables

-61y-10=0

We move all terms containing y to the left, all other terms to the right

-61y=10

y=10/-61

y=-10/61

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