3y-5y-(2y-6)=8y-2(9y-6)=

Solution for 3y-5y-(2y-6)=8y-2(9y-6)= equation:

3y-5y-(2y-6)=8y-2(9y-6)=

We move all terms to the left:

3y-5y-(2y-6)-(8y-2(9y-6))=0

We add all the numbers together, and all the variables

-2y-(2y-6)-(8y-2(9y-6))=0

We get rid of parentheses

-2y-2y-(8y-2(9y-6))+6=0


We calculate terms in parentheses: -(8y-2(9y-6)), so:

8y-2(9y-6)

We multiply parentheses

8y-18y+12

We add all the numbers together, and all the variables

-10y+12

Back to the equation:

-(-10y+12)


We add all the numbers together, and all the variables

-4y-(-10y+12)+6=0

We get rid of parentheses

-4y+10y-12+6=0

We add all the numbers together, and all the variables

6y-6=0

We move all terms containing y to the left, all other terms to the right

6y=6

y=6/6

y=1