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3y-6(y+3)=4(3y+2)-11
We move all terms to the left:
3y-6(y+3)-(4(3y+2)-11)=0
We multiply parentheses
3y-6y-(4(3y+2)-11)-18=0
We calculate terms in parentheses: -(4(3y+2)-11), so:We add all the numbers together, and all the variables
4(3y+2)-11
We multiply parentheses
12y+8-11
We add all the numbers together, and all the variables
12y-3
Back to the equation:
-(12y-3)
-3y-(12y-3)-18=0
We get rid of parentheses
-3y-12y+3-18=0
We add all the numbers together, and all the variables
-15y-15=0
We move all terms containing y to the left, all other terms to the right
-15y=15
y=15/-15
y=-1
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