3y-6=(y-1)+-10y+5

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Solution for 3y-6=(y-1)+-10y+5 equation: 



3y-6=(y-1)+-10y+5

We move all terms to the left:

3y-6-((y-1)+-10y+5)=0

We use the square of the difference formula

3y-((y-1)-10y+5)-6=0



We calculate terms in parentheses: -((y-1)-10y+5), so:

(y-1)-10y+5

We add all the numbers together, and all the variables

-10y+(y-1)+5

We get rid of parentheses

-10y+y-1+5

We add all the numbers together, and all the variables

-9y+4

Back to the equation:

-(-9y+4)



We get rid of parentheses

3y+9y-4-6=0

We add all the numbers together, and all the variables

12y-10=0

We move all terms containing y to the left, all other terms to the right

12y=10

y=10/12

y=5/6

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