3y-7+y+3/2=y+6

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Solution for 3y-7+y+3/2=y+6 equation: 



3y-7+y+3/2=y+6

We move all terms to the left:

3y-7+y+3/2-(y+6)=0

We add all the numbers together, and all the variables

4y-(y+6)-7+3/2=0

We get rid of parentheses

4y-y-6-7+3/2=0

We multiply all the terms by the denominator


4y*2-y*2+3-6*2-7*2=0

We add all the numbers together, and all the variables

4y*2-y*2-23=0

Wy multiply elements

8y-2y-23=0

We add all the numbers together, and all the variables

6y-23=0

We move all terms containing y to the left, all other terms to the right

6y=23

y=23/6

y=3+5/6

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