3y-y-4=-5(y-8)

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Solution for 3y-y-4=-5(y-8) equation: 



3y-y-4=-5(y-8)

We move all terms to the left:

3y-y-4-(-5(y-8))=0

We add all the numbers together, and all the variables

2y-(-5(y-8))-4=0



We calculate terms in parentheses: -(-5(y-8)), so:

-5(y-8)

We multiply parentheses

-5y+40

Back to the equation:

-(-5y+40)



We get rid of parentheses

2y+5y-40-4=0

We add all the numbers together, and all the variables

7y-44=0

We move all terms containing y to the left, all other terms to the right

7y=44

y=44/7

y=6+2/7

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