3y/2-(14y-3)/5=(y-4)/4

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Solution for 3y/2-(14y-3)/5=(y-4)/4 equation: 


y in (-oo:+oo)

(3*y)/2-((14*y-3)/5) = (y-4)/4 // - (y-4)/4

(3*y)/2-((14*y-3)/5)-((y-4)/4) = 0

(-1*(14*y-3))/5+(-1*(y-4))/4+(3*y)/2 = 0

(-1*2*4*(14*y-3))/(2*4*5)+(-1*2*5*(y-4))/(2*4*5)+(3*4*5*y)/(2*4*5) = 0

3*4*5*y-1*2*4*(14*y-3)-1*2*5*(y-4) = 0

60*y-122*y+64 = 0

64-62*y = 0

(64-62*y)/(2*4*5) = 0

(64-62*y)/(2*4*5) = 0 // * 2*4*5

64-62*y = 0

64-62*y = 0 // - 64

-62*y = -64 // : -62

y = -64/(-62)

y = 32/31

y = 32/31

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