3y/2=1200/y

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Solution for 3y/2=1200/y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(3*y)/2 = 1200/y // - 1200/y

(3*y)/2-(1200/y) = 0

(3*y)/2-1200*y^-1 = 0

3/2*y^1-1200*y^-1 = 0

(3/2*y^2-1200*y^0)/(y^1) = 0 // * y^2

y^1*(3/2*y^2-1200*y^0) = 0

y^1

(3/2)*y^2-1200 = 0

(3/2)*y^2-1200 = 0

DELTA = 0^2-(-1200*4*(3/2))

DELTA = 7200

DELTA > 0

y = (7200^(1/2)+0)/(2*(3/2)) or y = (0-7200^(1/2))/(2*(3/2))

y = 20*2^(1/2) or y = -20*2^(1/2)

y in { -20*2^(1/2), 20*2^(1/2)} 

y in { -20*2^(1/2), 20*2^(1/2) }

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