3y/2y-6/2y=17/3

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Solution for 3y/2y-6/2y=17/3 equation: 



3y/2y-6/2y=17/3

We move all terms to the left:

3y/2y-6/2y-(17/3)=0



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



We add all the numbers together, and all the variables

3y/2y-6/2y-(+17/3)=0

We get rid of parentheses

3y/2y-6/2y-17/3=0

We calculate fractions


(3y-18)/6y+(-34y)/6y=0

We multiply all the terms by the denominator


(3y-18)+(-34y)=0

We get rid of parentheses

3y-34y-18=0

We add all the numbers together, and all the variables

-31y-18=0

We move all terms containing y to the left, all other terms to the right

-31y=18

y=18/-31

y=-18/31

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