3y/4+13=40

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Solution for 3y/4+13=40 equation: 



3y/4+13=40

We move all terms to the left:

3y/4+13-(40)=0

We add all the numbers together, and all the variables

3y/4-27=0

We multiply all the terms by the denominator


3y-27*4=0

We add all the numbers together, and all the variables

3y-108=0

We move all terms containing y to the left, all other terms to the right

3y=108

y=108/3

y=36

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